Theoretically, PCB (Printed Circuit Board) current carrying capacity is determined by cross-sectional area of trace and temperature rise. Furthermore, cross-sectional area of trace is directly proportional to trace width and copper thickness. Well, here comes a question: does this rule also apply to the relationship between current carrying capacity and trace cross-sectional area, that is, is trace carrying capacity directly proportional to its cross-sectional area? Under the same temperature rise that is 10°C, a 10mil-trace with 1oz copper weight is capable of withstanding current of 1amp at most and we rest assured that a 50mil-trace is capable of withstanding current larger than 1amp.

Then how exactly is the maximum current it is able to hold, 5amps based on a simple multiple calculation? It’s actually far more complicated than that. According to MIL-STD-275, we are told that the maximum current a 50mil-trace can stand is 2.6amps.

Nevertheless, the table above has been gradually replaced by IPC-2221 Generic Standard on Printed Board Design as a reference based on which a printed circuit board is accurately designed.

Copper Thickness Measurement Unit

Prior to genuine discussion, it’s necessary to wiki a unit applied for copper thickness, ounce (oz). It is generally accepted as a unit for weight measurement but in circuit board design, it has been employed for copper thickness measurement. When it comes to the conversion on copper thickness by ounce, some rules should be kept in mind. Because specifications of copper are measured by copper weight per square feet, 1oz that is usually mentioned actually refers to the fact that each square feet of this copper is 1oz in terms of weight. Under such cases, the thicker copper is, the more it weighs since copper weight is directly proportional to its thickness. As a result, copper thickness can be represented by weight unit, ounce. Furthermore, ounce can be also transferred into units of millimeter or mil. Some ordinary conversions are listed below:
0.5oz = 0.0007inch = 0.7mils = 0.018mm
1.0oz = 0.0014inch = 1.4mils = 0.035mm
2.0oz = 0.0034inch = 2.8mils = 0.070mm

Relationship between PCB Copper Foil Cross-Sectional Area and Maximum Current Carrying Capacity and Temperature Rise

Based on the explanation of Section 6.2 in IPC-2221, that is, Conductive Material Requirements, current carrying capacity can be further classified into two types: internal conductors and external conductors. Maximum current carrying capacity of internal conductors is defined as half of that of external conductors. Table 6-4 in IPC-2221 demonstrates the relationship between copper foil cross-sectional area, temperature rise and maximum current carrying capacity among external conductors and internal conductors.

Moreover, a simplified formula has been summarized based on the tables above: I = KΔT0.44A0.75

In this formula, K is a correction factor. It is equivalent to 0.024 in terms of internal conductors and 0.048 for external conductors. ΔT is the Max. temperature difference, indicating the temperature difference between heating copper and ambient temperature with its unit to be degrees Celsius (°C). A refers to cross-sectional area of copper trace with its unit to be square mil (mil²). I refers to current carrying capacity with its unit to be ampere (Amp).

Owing to the development of electronic technology, some online trace width calculators are available for circuit board designers. It’s such a handy tool that as soon as demanded current and copper weight are filled, corresponding trace width of internal conductors and external conductors will be provided.PCB Trace Width Calculator and ANSI IPC-2221A PCB Trace Width Calculator belong to the tools introduced just now.